diketahui f(x) = 2x + 1/ 3x +4, x ≠ -4/3 dan f–¹ adalah invers f. nilai f–¹(3) adalah...

y =(2x + 1)/(3x + 4)
y(3x + 4) = 2x + 1
3xy + 4y = 2x + 1
3xy - 2x = 1 - 4y
x(3y - 2) = 1 - 4y
x = (1 - 4y)/(3y - 2)
f^-1(x) = (1 - 4x)/(3x - 2)
f^-1(3) = (1 - 4.3)/(3.3 - 2) = -11)/7

f(x) =2x+1/3x+4
f–¹ = -4x+1/3x-2
f–¹(3) = -4(3)+1/3(3)-2
= -11/7