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Matematika
Tasyatm1
Pertanyaan
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1 Jawaban
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1. Jawaban gustanika
Suku pertama
U₁ = 2²⁻ⁿ
U₁ = 2²⁻¹
U₁ = 2¹
U₁ = 2
Suku kedua
U₂ = 2²⁻²
U₂ = 2⁰
U₂ = 1
Rasio
r = U₂/U₁
r = 1/2
Jumlah tak hingga
S∞ = a/(1-r)
S∞ = U₁/(1-r)
S∞ = 2/(1-1/2)
S∞ = 2/(1/2)
S∞ = 2 : 1/2
S∞ = 2 × 2/1
S∞ = 4/1
S∞ = 4