tolong bantu jawab dong.. please

no. 5.a
L = [tex] \frac{a.t}{2} [/tex]
x² - 4 = [tex] \frac{(x + 2)t}{2} [/tex]
2(x² - 4) = (x + 2)t
2x² - 8 = (x + 2)t
t = [tex] \frac{2 x^{2} - 8}{x + 2} [/tex]
t = [tex] \frac{(2x - 4)(x + 2)}{(x + 2)} [/tex]
t = 2x- 4

no. 5.b
x = 3
t  = 2(3) - 4 = 6 - 4 = 2
a = 3 + 2 = 5
L = 3² - 4 = 9 - 4 = 5

Ok, jangan lupa terima kasih...!