Dlk ksp L(OH)3=2,7×10-23, ph larutan jenuh basa tersebug adalah

L(OH)3 ==>L3+ + 3OH-
s s x 3s
ksp = s x 3s^3
ksp = 27s^4
2,7 x 10^-23 = 27s^4
s^4 = 10^-24
s = 10^-6

OH- = v.asam x Mb
OH- = 3 x 10^-6
pOH = - log OH-
pOH = - log 10^-6
pOH = 6
pH = pKw - pOH
pH = 14 - 6
pH = 8