Tentukan penyelesaian dari persamaan berikut! tg(2x - 3π/4) = 1, untuk 0 ≤ x ≤ 2π . . . .

Bab Trigonometri
Matematika SMA Kelas X

tan (2x - 3π/4) = 1

(8x - 3π)/4 = π/4
8x - 3π = π
8x = 3π + π
x = 4π/8 = π/2

(8x - 3π)/4 = 5π/4
8x - 3π = 5π
8x = 3π + 5π
x = 8π/8
x = π

(8x - 3π)/4 = 9π/4
8x - 3π = 9π
8x = 9π + 3π
x = 12π/8
x = 3π/2

(8x - 3π)/4 = 13π/4
8x - 3π = 13π
8x = 13π + 3π
x = 16π/8
x = 2π

HP = { π/2, π, 3π/2, 2π }