Matematika

Pertanyaan

diketahui; log 2=0,3010 ,log 3=0,4771 dan log 7=0,8451 tentukan:
a.log 42=
b.log 3,5=

2 Jawaban

  • a log 42= log 2x3x7 = log 2+ log 3 + log 7
    log 42= 0,3010 + 0,4471 + 0.8451
    log 42 = 1,5932

    b log 3,5 = log 7/2 = log 7 - log 2
    log 3,5 = 0.8451 - 0.3010
    log 3,5 = 0,5441
  • a.log 42=log 6.7=log 2.3.7=log 2+log 3+log 7=0.3010+0.4771+0.8451= 1.6232

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