diketahui; log 2=0,3010 ,log 3=0,4771 dan log 7=0,8451 tentukan: a.log 42= b.log 3,5=
Matematika
jputri90
Pertanyaan
diketahui; log 2=0,3010 ,log 3=0,4771 dan log 7=0,8451 tentukan:
a.log 42=
b.log 3,5=
a.log 42=
b.log 3,5=
2 Jawaban
-
1. Jawaban dimaspamungkas5
a log 42= log 2x3x7 = log 2+ log 3 + log 7
log 42= 0,3010 + 0,4471 + 0.8451
log 42 = 1,5932
b log 3,5 = log 7/2 = log 7 - log 2
log 3,5 = 0.8451 - 0.3010
log 3,5 = 0,5441 -
2. Jawaban nursalamalamin
a.log 42=log 6.7=log 2.3.7=log 2+log 3+log 7=0.3010+0.4771+0.8451= 1.6232