sebanyak 0,37gram Ca(OH)2 dilarutkan dalam air sampai volumenya 250mL, maka pH larutan adalah(Ar Ca=40, O=16)

M = 0,37/(40 + 2(16) + 2(1)) × 1000/250
= 0,37/74 × 1000/250
= 5/1000 × 1000/250
= 1/1 × 1/50
= 1/50
= 2 × 10^-2

[OH-] = 2 × 2 × 10^-2 = 4 × 10^-2

pOH = 2 - log 4
pH = 12 + log 4