TOLONG JAWAB SECEPATNYA No 9- 16 untuk ulangan besok....ada cara dan harus benar (materi balok)

no. 9
AB = 12cm BC= 8cm AE=5cm
a) Panjang AF = AF^2 = AB^2 + BF^2
AF^2 = 12^2 + 5^2
AF^2 = 144+25
AF = akar (169) = 13
b) AC = akar (AB^2 + BC^2)
AC = akar (12^2 + 8^2)
AC = akar (144 + 64)
AC = √(208) = 4√13
c) AH = akar (AE^2 + EH^2)
AH = akar (5^2 + 8^2)
AH = akar (25+64)
AH = √89
no. 10
P=12cm l=8cm T=4cm
diagonal ruang = √12^2 + 8^2 + 4^2
diagonal ruang = √144+64+16
diagonal ruang = 224 = 4√14
no. 11
AB = 12cm BC=8cm AE = 6cm
BG = √BC²+CG²
BG = √8²+6²
BG = √64+36
BG = √100 = 10 cm
Luas ABGH = AB × BG
Luas ABGH = 12 × 10 = 120cm
no. 12
Luas permukaan = 2×(pl+lt+tp)
Luas permukaan = 2×(9×8 + 8×4 + 4×9)
Luas permukaan = 2×(72+32+36)
Luas permukaan = 2×140 = 280cm²
Volume = p×l×t = 9×8×4=288cm³
no. 13
Lp= 2×(pl+lt+tp)
108 = 2×(3p +3×4 + 4p)
108 = 2×(12+ 7p)
108 = 24+14p
14p = 108-24
14p = 84
p = 84/14 = 6 cm
no. 14
p = 8 l = 3 t = 5
Lp = 2×(pl+lt+tp)
Lp = 2×(8×3 + 3×5 + 5×8)
Lp = 2×(24+15+40)
Lp = 2×79 = 158 cm²
no. 15
KL = 24 LM = 18 KO=11
LN = √KL²+KN²
LN = √24²+18²
LN = √576 + 324
LN = √900 = 30 cm
Luas LNRP = LN×LP = 30 × 11 = 330
no. 16
AB = 8cm BC = 6cm BF= 3cm
a) diagonal bidang AC
AC = √AB²+BC²
AC = √8²+6²
AC = √64+36
AC = √100 = 10
b) diagonal ruang AG terletak pada bidang diagonal ACGE
panjang AG dapat dicari jika panjang AC atau EG dan AE atau CG diketahui.
CG = BF =  3cm AC = 10cm
AG = √AC² + CG²
AG = √10² + 3²
AG = √100+9 = √109 = 10,4 cm
c) L ACGE = AC × CG = 10 × 3 = 30cm