Matematika

Pertanyaan

tolong dijawab pertanyaan nya
tolong dijawab pertanyaan nya

2 Jawaban

  • TP1= 288 TP2= 108 TP3= 372
  • a. L = ½ × (a+b) × t
    = ½ × (12+20) × 18
    = ½ × 32× 18
    = 16 × 18
    = 288 cm²

    b. L = ½ × (a+b) × t
    = ½ × (5+8) × 12
    = ½ × 13 × 12
    = 13 × 6
    = 78 cm²

    c. t = √13²-5²
    = 12
    L = ½ × (a+b) × t
    = ½ × (16+18) × 12
    = ½ × 34 × 12
    = 34 × 6
    = 204 cm²