Matematika

Pertanyaan

bayangan titik W (2,6) dilatasi dengan pusat (3,-2) dan skala -2 adalah

1 Jawaban

  • [tex]\displaystyle\left[\begin{array}{ccc}x'\\y'\end{array}\right]=k\left[\begin{array}{ccc}x-a\\y-b\end{array}\right]+\left[\begin{array}{ccc}a\\b\end{array}\right]\\\left[\begin{array}{ccc}x'\\y'\end{array}\right]=-2\left[\begin{array}{ccc}2-3\\6+2\end{array}\right]+\left[\begin{array}{ccc}3\\-2\end{array}\right]\\\left[\begin{array}{ccc}x'\\y'\end{array}\right]=-2\left[\begin{array}{ccc}-1\\8\end{array}\right]+\left[\begin{array}{ccc}3\\-2\end{array}\right][/tex]
    [tex]\displaystyle \left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}2\\-16\end{array}\right]+\left[\begin{array}{ccc}3\\-2\end{array}\right]\\\boxed{\boxed{\left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}5\\-18\end{array}\right]}}[/tex]

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