Suatu fungsi dirumuskan f(2x-3) = 4x+3 nilai dari f(9)= A.27 B.25 C.24 D.22

f(2x - 3) = 4x + 3

2x - 3 = 9
2x = 12
x = 6

f(2 × 6 - 3) = 4 × 6 + 3
f(12 - 3) = 24 + 3
f(9) = 27
Jawaban: A

f(2x-3) = 4x + 3
2f(x) - 3 = 4x + 3
2f(x) = 4x + 3 + 3
2f(x) = 4x + 6
f(x) = 2x + 3.

f(9) = 2x + 3
f(9) = 2(9) + 3
f(9) = 18 + 3
f(9) = 21

Semoga membantu;)