Prisma segitiga tegak ABC.DEF dengan AB = 60, BC= 48 cm, AC= 36 cm dan tingginya 80 cm. Prisma ini dibuat modelnya sehingga rasio luas permukaan prisma semula d

Materi : Prisma dan Limas
Kelas : 8 SMP

s = 1/2 (AB + BC + AC)
s = 1/2 (60 + 48 + 36)
s = 1/2 × 144
s = 72

L ∆ = √[s (s - a)(s - b)(s - c)]
L ∆ = √[72 (72 - 60) (72 - 48) (72 - 36)]
L ∆ = √[72(12)(24)(36)]
L ∆ = √746496
L ∆ = 864 cm²

LP P semula = 2 L ∆ + (tp × K ∆)
= (2 × 864) cm² + 80(60 + 48 + 36) cm²
= 1728 cm² + (80 × 144) cm²
= 1728 cm² + 11520 cm²
= 13248 cm²

LP semula : LP model = 16 : 1
13248 : LP model = 16 : 1
LP model = 13248/16
LP model = 828 cm²

L ∆ model = L∆ semula / 16
L ∆ model = 864 / 16
L ∆ model = 54 cm²

tinggi prisma model = t semula / √16
tp model = 80/4
tp model = 20 cm

V prisma model = L∆ model × tp model
V prisma model = 54 cm² × 20 cm
V prisma model = 1080 cm³