tentukan nilai nilai perbandingan trigonometri pada titik L (-12,16)

sisi miring = (16^2 + (-12)^2) ^1/2
                 = (400)^ 1/2
                 = 20

hypotenuse: 20
sisi seberang: 16
sisi adjacent: -12

sin: 16/20
cos: -12/20
tan: -16/12

L(-12, 16) di kuadran 2 => x = -12, y = 16
r = √(12^2 + 16^2) = √(144 + 256) = √(400) = 20

Sin ¢ = y/r = 16/20 = 4/5 => cosec ¢ = 5/4
Cos ¢ = x/r = -12/20 = -3/5 => sec ¢ = -5/3
Tan ¢ = y/x = 16/-12 = -4/3 => cot ¢ = -3/4