Matematika

Pertanyaan

Bantu dong... Turunan Fungsi Aljabar
Bantu dong... Turunan Fungsi Aljabar

1 Jawaban

  • ^ tanda pangkat
    akar pangkat 1/2
    d. (1/2)x^-1/2 + 2x^1/2
    turunannya
    = (1/2)(-1/2) x^(-1/2-1) + 2(1/2) x^(1/2-1)
    = -1/4 x^-3/2 + x^-1/2
    = -1/4x^3/2 + 1/x^1/2
    = -1/(4x√x) + 1/√x

    e. 3x (x^1/3) - 1/x^1/3
    3 x^(1+1/3) - x^-1/3
    3x^(4/3) - x^-1/3
    turunannya
    3(4/3)x^(4/3-1) - (-1/3)x^(-1/3-1)
    4x^1/3 + (1/3)x^(-4/3)
    = 4(³√x) + 1/(3x^4/3)
    = 4(³√x) + 1 / (3x ³√x)

    f. (x² - 1/x²)(x² - 1/x²)
    = x⁴ - 2 + 1/x⁴
    = x⁴ + x^-4 - 2
    = 4x³ - 4x^-5
    = 4x³ - (4/x^5)