pada layang layang PQRS disamping, panjang PR=12cm, Qs= (x + 3)cm, dan luas PQRS = 96 Cm2, hitunglah a. nilai x b. panjang QS

a.
Luas = 1/2 diagonal 1 x diagonal 2
96 = 1/2 12(x+3)
96x2 = 12(x+3)
192 = 12x + 36
192-36 = 12x
156 = 12x
156/12 = x
13 = x

b.Qs = x + 3
= 13 + 3
= 16