Matematika

Pertanyaan

[tex] \frac{ cot^{2}x }{csc x+ 1} =1[/tex], 0 < x < 90. maka x = ...

1 Jawaban

  • cot²x + 1 = csc²x
    cot²x = csc²x - 1

    cot²x/(csc x  + 1) = 1
    (csc²x - 1)/(csc x + 1) = 1
    (csc x + 1) (csc x - 1) / (csc x + 1) = 1
    csc x - 1 = 1
    csc x = 1 + 1
    csc x = 2
    1/sin x = 2
    sin x = 1/2
    sin x = sin 30

    maka x = 30°

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