Diketahui rumus fungsi f(x)=ax+b. Jika f(-4)=13 dan f(3)= -1, maka nilai f(-2)... a. 11 b. 9 c. 7 d. -2 *disertakan caranya yaa, terima kasih

Langsung aja y

f(-4) = -4a + b = 13
f(3) = 3a + b = -1
_____________-
-7a = 14
a = -2

3a + b = -1
b = -1 - 3(-2)
b = -1 + 6
b = 5

f(x) = ax + b
f(x) = -2x + 5

f(-2) = -2(-2) + 5
f(-2) = 4 + 5
f(-2) = 9

jawabannya B

semoga berguna +_+

f(-4) = a × -4 +b = 13
-4a + b = 13

f(3) = a × 3 + b = -1
3a + b = -1

eliminasi

-4a + b = 13
3a + b = -1
___________ -
- 7a = 14
a = 14 ÷ -7 = -2

b = ?

3 × -2 + b = -1
-6 + b = -1
b = -1 + 6

b = 5

f(x) = -2x + 5

f(-2) = -2 × -2 + 5

= 4 + 5 = 9

jadi, f(-2) = 9


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