tentukan bayangan dari parabola y = x^2 + 1 yang ditranslasikan oleh T = (1 , 2) dilanjutkan oleh dilatasi [O , 3]!

Transformasi

(x', y') = (x,y) + [ T(1,2)]  = (x+1), (y+2)
x' = x+1
y' = y + 2

(x" , y") = (x',y') [D,0,3] = (3x', 3y')
x" =3x'
y" = 3y'

.x" = 3x' = 3(x+1) = 3x + 3
3x = x" - 3
x = 1/3 x" - 1

y" = 3y' = 3(y+2) = 3y + 6
3y = y" - 6
y = 1/3 y" - 2

y = x² + 1 --> T(1,2) --> D[0, 3]
(1/3 y" -2)   = (1/3 x"' -1)² +1
1/3 y" -2 = 1/9 x"² - 2/3 x" + 1 + 1 ...kalikan 9
3y - 18 = x² - 6x + 18
3y = x² - 6x + 36
atau
y = 1/3 x² - 2x + 12