Tolong ya......... Terima kasih
Matematika
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Pertanyaan
Tolong ya......... Terima kasih
1 Jawaban
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1. Jawaban whongaliem
1) lihat Δ BCD
∠ BDC + ∠ CBD + ∠ BCD = 180°
∠ BDC + 43° + 82° = 180°
∠ BDC + 125° = 180°
∠ BDC = 180° - 125°
∠ BDC = 55°
a) ∠ BAC = ∠ BDC (menghadap busur yang sama)
= 55°
∠ BOC = 2 x ∠ BDC
= 2 x 55°
= 110°
∠ OBC = (180 - 110) / 2
= 70 / 2
= 35°
b) ∠ OBD = ∠ CBD - ∠ OBC
= 43° - 35°
= 8°
c) ∠ OCD = ∠ BCD - ∠ OCB
= 82° - 35°
= 47°
2.a) ∠ DAC = ∠ ACB (berseberangan dalam)
b) ∠ QBC = ∠ BAD (sehadap)