diketahui vektor p(-1,2) dan q(2,5), tentukan vektor t jika |p-t| = |q-t|

p-t = [-1 - x, 2-y]
q-t = [2-x, 5-y]
|p-t| = |q-t|
|-1 - x, 2-y| = |2-x, 5-y|
√(-1 - x)²+ (2-y)² = √(2-x)² + (5-y)² (kedua akar bisa dihilangkan)
(-1 - x)²+ (2-y)² =(2-x)² + (5-y)²
1+2x+x² + 4-4y+ y² = 4-4x+ x² + 25-10y+y²
1+2x+x² + 4-4y+ y²- 4+4x-x² - 25+10y-y²
-24 + 6x + 6y = 0
6x + 6y = 24
x + y = 4
X = 2, Y = 2
Vektor t = [2,2]