tentukan rasio,suku ke-10,dan jumlah 10 suku pertama dari deret geometri berikut 2+1+1/2+1/4+...

a = 2
rasio(r) = U2/U1 = 1/2
U10 = a.r^(n-1)
U10 = 2.(1/2)^9
= 2(1/512)
= 1/256
S10 = a(1 - r^n) / 1-r
= 2(1 - (1/2)^10) / 1-(1/2)
= 2(1 - 1/1024) / (1/2)
= 2(1023/1024) / (1/2)
= (1023/512) × 2
= 1023/256