Terdapat 4L larutan NH4CL 0,01M.jika Kb=10*-9,pH larutan haramnya adalah

[H+] = akar (Kw/Ka x M.Garam)
[H+] = akar (10^-5 x 10^-2)
[H+] = akar 10^-7
[H+] = 10^-3,5
pH = -log[H+]
pH =3,5