suatu fungsi F(x) = ax+b, jika F(2) = -2 dan F(-3) = 13 Maka hitunglah nilai dari F(4)+F(5)

f(x) = ax + b

f(2) = a×2+b = 2a + b = -2
f(-3) = a×3+b = -3a+b = 13 --
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5a/5 = -15/5 = -3

persamaan I
= a×2+b = -2
= -3×2+b = -2
= -6 + b = -2
b = -2+6
b = 4

a = -3
b = 4

f(4) = -3 × 4 + 4
= -12 + 4 = -8

f(5) = -3 × 5 + 4
= -15 + 4 = -11

f(4) + f(5)
= -8 + - 11
= -19

Fx = ax + b
F2 = -2. = 2a + b = -2
F-3= 13. = -3a + b= 13
2a + b = 2 - (-3a + b = 13)
5a = 15, a = 5
2a + b = -2
2.5 + b = -2
b = -12
F4 = 4.5 + -12 = 20-12 = 8
F5 = 5.5+ -12 = 25-12 = 13
F4+ F5 = 8 + 13 =21