Matematika

Pertanyaan

perbandingan sisi sisi segitiga 3:4:2
luasnya 3 akar 15
mka kelilingnya?

1 Jawaban

  • sisi-sisinya
    3x ; 4x ; 2x

    K = 3x + 4x + 2x = 9x
    S = 1/2 × 9x = 9/2 x

    Luas = 3 akar15
    akar(s(s-a)(s-b)(s-c)) = 3 akar15
    akar(9/2 x (9/2x - 3x)(9/2x - 4x)(9/2x - 2x)) = 3 akar15
    akar(9/2x × 3/2x × 1/2x × 5/2x) = 3 akar15
    akar(135/8 x^3) = 3 akar15
    135/8 x^3 = 9×15
    135/8 x^3 = 135
    x^3 = 135 × 8/135
    x^3 = 8
    x^3 = 2^3
    x = 2

    Jadi Keliling= 9x = 9×2 = 18 cm

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