Titik P terletak pada garis AB. Koordinat titik A(11,3,-2) B(6,8,3) jika AB:BP=5:2 maka kordinat P adalah

AB/BP = 5/2
(b - a)/(p - b) = 5/2
(6,8,3) - (11,3,-2) / (p - (6,8,3) = 5/2

[(6 - 11),(8 - 3),(3 - (-2)] / [P  - (6,8,3)] = 5/2
(-5,5,5) / [P  - (6,8,3)] = 5/2

[P  - (6,8,3)] = 2/5. (-5,5,5)

[P  - (6,8,3)] =  (-2,2,2)
P = (-2,2,2) + (6,8,3)

P = [(-2 + 6),(2 + 8),(2 + 3)]

P = (4,10,5)