vektor segaris ,no. 18

Ya pertama tama cari k karena segaris

AB = b - a = (2, 1, 1) - (-3, -2, 3) = (5, 3, -2)

A. C(12, 11, 3) => AC = c - a = (12, 11, 3) - (-3, -2, 3) = (15, 13, 0) ≠ k . AB

B. C(12, 7, 3) => AC = c - a = (12, 7, 3) - (-3, -2, 3) = (15, 9, 0) ≠ k . AB

C. C(12, 5, 7) => AC = c - a = (12, 5, 7) - (-3, -2, 3) = (15, 7, 4) ≠ k . AB

D. C(12, 7, -3) => AC = c - a = (12, 7, -3) - (-3, -2, 3) = (15, 9, -6) = 3(5, 3, -2)
= 3 AB

Jadi D yang segaris dengan A dan B