buktikan bahwa 1+cot2b/cotb×sec2b=cotb
Matematika
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Pertanyaan
buktikan bahwa 1+cot2b/cotb×sec2b=cotb
1 Jawaban
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1. Jawaban bapakdr
1 + cot²b = 1/sin²b
cot b × sec²b = (cos b/sin b) × (1/cos²b)
= (1/sin b) × (1/cos b)
= 1 / sin b cos b
jadi
(1 / sin²b) / (1 / sin b cos b)
= (1 / sin²b) × (sin b cos b / 1)
= sin b cos b / sin²b
= cos b / sin b
= cot b