hitung luas daerah antara kurva dari garis y=x² dan y=x+6

x² = x + 6
x² - x - 6 = 0
(x - 3)(x + 2) = 0
x = 3 dan x = -2
x + 6 - x² dx interval 3 dan -2
= 1/2x² + 6x - 1/3x³
= 1/2(3)²+6(3)-1/3(3)³ - {1/2(-2)²+6(-2)-1/3(-2)³}
= 9/2 + 18 - 9 - {2 - 12 + 8/3}
= 9/2 + 9 + 10 - 8/3
= 9/2 + 19 - 8/3
= 27/6 + 114/6 - 16/6
= 125/6
= 20(5/6)