lim mendekati 0 cos 2x - cos x / x^2
Matematika
Agungfahrizals
Pertanyaan
lim mendekati 0 cos 2x - cos x / x^2
2 Jawaban
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1. Jawaban abyandaffa11
cos 2x - cos x / x^2
-2 sin 3x/2 sin x/2 / x . x
= -2 × 3/2 × 1/2
= -3/2
= -1,5 -
2. Jawaban DB45
cara lain..
lim(x->0) (cos 2x - cos x) /x²
lim(x->0) { 1- 2 sin² x - (1 - 2 sin² ¹/₂ x)] / (x²)
lim(x->0) {1 - 2sin² x -1 + 2 sin² ¹/₂ x) x²
lim(x->0) (- 2 sin² x + 2 sin² ¹/₂ x) / x²
lim(x->0) -2 sin² x / x² + lim(x->0) 2 sin² ¹/₂ x / x²
= -2 + 2 (¹/₂)²
= -2 + ¹/₂
= - ³/₂