pada segitiga ABC diketahui BC = 2√2 cm , AC = 4 cm dan < A = 30° . Dengan demikian < C =

[tex] \frac{sin(A)}{a} = \frac{sin(B)}{b} \\ \frac{sin(30)}{2 \sqrt{2} } = \frac{sin(B)}{4} \\ \frac{0.5}{2 \sqrt{2} } = \frac{sin(B)}{4} \\ \frac{2}{2 \sqrt{2}} = sin(B) \\ \frac{1}{\sqrt{2}} = sin(B) \\ \ \textless \ B = 45 \\[/tex]
[tex]C = 180 - B - A \\ C = 180 - 45 - 30 \\ C = 105[/tex]