150 ml larutan H2SO4 0,2 M direaksikan dengan 200 ml larutan NH4OH 0,2 M. Tentukan pH larutan campuran! (Kb NH4OH = 10^-5

dik : NH4OH = 200 ml×0,2 M = 40mmol
H2SO4 = 150ml × 0,2 M = 30 mmol
Kb = 10^-5
dit : pH
jawab :
NH4OH + H2SO4-->(NH4)2SO4 + H2O
m : 40mmol_30mmol
b : -30mmol_-30mmol_-30mmol
_________________________ -
s : 10 mmol_0_30mmol

[OH-] = Kb×Bl/garam
[OH-] = 10^-5×10/30
[OH-] = 0,3 × 10-5
[OH-] = 3 × 10^-6
[OH-] = 6 - log 3
pH = 8 + log 3
pH = 8,47