simpangan baku dari 3,5,6,6,7,10,12

langsung aja y

X = (3+5+6+6+7+10+12) / 7
X = 49/7 = 7

Sb = √(3-7)²+(5-7)²+2(6-7)²+(7-7)²+(10-7)²+(12-7)² / 7

Sb = √16+4+2+0+9+25 / 7

Sb = √56/7

Sb = √8

Sb = 2√2

semoga berguna +_+