Matematika

Pertanyaan

tolong jawab no 19 a-d...
perlu skrg nih...pake caranya ya..
makasih..
tolong jawab no 19 a-d... perlu skrg nih...pake caranya ya.. makasih..

1 Jawaban

  • 19.A.) titik (2,0) (0,-4)
    y-y1/y2-y1 = x-x1/x2-x1
    y-0/-4-0 = x-2/0-2
    y/-4 = x-2/-2
    -2y = -4x+8
    -y = -2x+4
    y-2x = -4

    B.) (3,0) (0,-2)
    m = -2-0/0-3
    m = -2/-3 = 2/3
    (-6,0)
    y-y1 = m(x-x1)
    y-0 = 2/3(x+6)
    y = 2/3x+4 .....×3
    3y = 2x+12
    3y-2x-12=0

    C.) tinggi tembok = √10²- 6²
    tinggi tembok = √100-36
    tinggi tembok = √64 = 8 cm

    kemiringan tangga = vertikal/horizontal
    kemiringan tangga = 8cm/6cm
    kemiringan tangga = 4/3

    D.)4p+3q =-4|×3|12p+9q=12
    ....3p-2q = 14|×4|12p-8q=56
    ..............................------------- -
    ..............................17q = -68
    ..................................q = -4

    12p+9(-4) = -12
    12p = 24
    P = 2
    p= x
    q=y

    x-3y = 2-(-4)
    = 2+12
    = 14