tolong jawab no 19 a-d... perlu skrg nih...pake caranya ya.. makasih..
Matematika
bomat1
Pertanyaan
tolong jawab no 19 a-d...
perlu skrg nih...pake caranya ya..
makasih..
perlu skrg nih...pake caranya ya..
makasih..
1 Jawaban
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1. Jawaban melii3
19.A.) titik (2,0) (0,-4)
y-y1/y2-y1 = x-x1/x2-x1
y-0/-4-0 = x-2/0-2
y/-4 = x-2/-2
-2y = -4x+8
-y = -2x+4
y-2x = -4
B.) (3,0) (0,-2)
m = -2-0/0-3
m = -2/-3 = 2/3
(-6,0)
y-y1 = m(x-x1)
y-0 = 2/3(x+6)
y = 2/3x+4 .....×3
3y = 2x+12
3y-2x-12=0
C.) tinggi tembok = √10²- 6²
tinggi tembok = √100-36
tinggi tembok = √64 = 8 cm
kemiringan tangga = vertikal/horizontal
kemiringan tangga = 8cm/6cm
kemiringan tangga = 4/3
D.)4p+3q =-4|×3|12p+9q=12
....3p-2q = 14|×4|12p-8q=56
..............................------------- -
..............................17q = -68
..................................q = -4
12p+9(-4) = -12
12p = 24
P = 2
p= x
q=y
x-3y = 2-(-4)
= 2+12
= 14