persamaanya lingkaran yg berpusat diP(-3,4)dan meyingung hairs 6x-8y+25=0 mempuyai jari -jari : A.1/10 B21/2 C.5 D 73/10 E.10

misal 6x - 8y + 25 = 0 ---> ax + by + c = 0

P(-3, 4) = (m, n)

r = am + bn + c / akar (a^2 + b^2)
= 6(-3) + 4(-8) + 25 / akar (6^2 + (-8)^2)
= -18 - 32 + 25 / akar (36 + 64)
= -25 / akar 100
= -25/10
= -5/2
= -2 1/2 (dimutlakin)
= 2 1/2
Jawaban: B

rumus jarak
garis: ax + bx + c = 0
ke titik (x₁,y₁)
r= |ax₁+by₁+c / √a² + b²|
r=|6.(-3) + (-8).4+25/√6² + -8²|
 = |-18 - 32 + 25 / 10|
 = |-25/10|
 = 2 1/2