suatu fungsi f dinyatakan dengan rumus f(×)=px+q,jika f(-4) = 19 dan f(6) = -11,tentukanlah :A.System persamaan dalam p dan q B.selesaikan system persamaan ters

f(x) = px + q
f(-4) = p(-4) + q = 19
f(-4) = -4p + q = 19

f(x) = px + q
f(6) = p(6) + q = - 11
f(6)= 6p + q = -11

Eliminasi:

-4p+ q = 19
6p + q = -11
__________ -
-10 p = 30
p = - 3

substitusi:
6p + q = -11
6(-3) + q = -11
-18 + q = -11
q = -11 + 18
q = 7

nilai P + q = -3 + 7 = 4

Diket : f(X) = px + q
f(-4)= p.-4 + q = 19
f(6) = p. 6 + q = -11
Dit : A. sistem persamaan
B. penyelesaian
c. Nilai P + q
Jawab
A. sistem persamaan
f(-4)= -4p + q = 19
f(6) = 6p + q = -11
jadi, persamaannya
-10p = 30
B. penyelesaian
-10p = 30
p = 30/-10
p = -3
C. Nilai p + q
6p + q = -11
6×-3 + q = -11
q = -11 + 18
q = 7

p + q = -3 + 7 = 4