Matematika

Pertanyaan

Jika A^2x = 2 maka A^5x - A^-5x /A^3x - A^-3x

1 Jawaban

  • A^2x = 2 ...... kedua ruas dipangkatkan 1/2
    (A^2x)^1/2 = 2^1/2
    A^x = 2^1/2

    Maka
    A^5x = (A^x)^5 = (2^1/2)^5 = 2^5/2 = 2^2 . 2^1/2 = 4√2 => A^-5x = 1/(4√2)
    A^3x = (A^x)^3 = (2^1/2)^3 = 2^3/2 = 2 . 2^1/2 = 2√2 => A^-3x = 1/(2√2)

    (A^5x - A^-5x)/(A^3x - A^-3x)
    = (4√2 - 1/(4√2)) / (2√2 - 1/(2√2) ...... kali (4√2)/(4√2)
    = (32 - 1)/(16 - 2)
    = 31/14

    = 2 3/14

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