Jika A^2x = 2 maka A^5x - A^-5x /A^3x - A^-3x
Matematika
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Pertanyaan
Jika A^2x = 2 maka A^5x - A^-5x /A^3x - A^-3x
1 Jawaban
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1. Jawaban arsetpopeye
A^2x = 2 ...... kedua ruas dipangkatkan 1/2
(A^2x)^1/2 = 2^1/2
A^x = 2^1/2
Maka
A^5x = (A^x)^5 = (2^1/2)^5 = 2^5/2 = 2^2 . 2^1/2 = 4√2 => A^-5x = 1/(4√2)
A^3x = (A^x)^3 = (2^1/2)^3 = 2^3/2 = 2 . 2^1/2 = 2√2 => A^-3x = 1/(2√2)
(A^5x - A^-5x)/(A^3x - A^-3x)
= (4√2 - 1/(4√2)) / (2√2 - 1/(2√2) ...... kali (4√2)/(4√2)
= (32 - 1)/(16 - 2)
= 31/14
= 2 3/14